Atotal of 378 tickets were sold for the school play. they were either adult tickets or student tickets. the number of students tickets sold was two times the number of adult tickets. how many adult tickets were sold?

252 students

126 adults

Step-by-step explanation:

x= #student tickets

y= #adult tickets

x+y=378       x=2y

2y+y=378

3y=378

y=126

                    x=2(126)

                     x=252

ANSWER:

Total number of adult tickets sold were 126.

SOLUTION:

Given, a total of 378 tickets were sold for the school play. They were either adult tickets or student tickets.  

The number of students tickets sold was two times the number of adult tickets.  

We need to find how many adult tickets were sold?

Let, the number of student tickets be x.

And the number of adult tickets be y.

Then, total number of tickets are 378

x + y = 378 --- eqn (1)

And, no. of student tickets are two times the no. of adult tickets

No. of student tickets =2 x no. of adult tickets

x = 2y --- eqn  (2)

Now, substitute the x value in (1)

2y + y = 378

3y = 378

y = 126

Hence, total number of adult tickets sold were 126

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)