In the election for student council, candidate a received 55% of the total votes, while candidate b received 1541 votes. if candidate c received 40% of the votes that candidate a received, how many total votes were cast?

6700

Step-by-step explanation:

Hello!

To solve this problem we must raise a small equation, consider the following!

1. the variable we call X is the total number of votes

2. If we add the votes of all the candidates, it will result in the total number of votes

3. number of votes for candidate A = X (55%) = 0.55X

4.number of votes for candidate b = 1541

5. number of votes for candidate C = 40% (0.55X) = (0.4) (0.55) X = 0.22X

we raise the equation

0.55X+1541+0.22X=X

Now we solve for X, using algebraic operations on both sides of the equation

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.