4. triangle abc has vertices a(-2, 0), b(0, 3), and c(2, 3) and is dilated by a factor of 2 using
the point (0, -1) as the point of dilation. the dilated triangle is named aa'b'c: what are
the coordinates of the vertices of the resulting triangle?

Step-by-step explanation:

When the dilation factor is k and the center of dilation is (a, b), the transformation relation is ...

  (x, y) ⇒ (a, b) + k((x, y) -(a, b)) = (kx +(1-k)a, ky +(1-k)b)

For k=2, (a, b) = (0, -1) the transformation is ...

  (x, y) ⇒ (2x, 2y +1)

So, the given vertices are dilated to ...

  A(-2, 0) ⇒ (2(-2), 2(0)+1) = A'(-4, 1)

  B(0, 3) ⇒ (2(0), 2(3)+1) = B'(0, 7)

  C(2, 3) ⇒ (2(2), 2(3)+1) = C'(4, 7)