Consider the two functions.

f(x) = x² – 8x + 7

do the minima of the two functions have the same x-value? yes or no

which of the functions has the greater minimum? g(x) or f(x)

(second function is the graph below)

They have the same x-value

f(x) has the greater minimum

Step-by-step explanation:

To find the vertex of a second degree equation, in this case the minimum value, we can use the following equation:

x = -b / 2a

Remember that a second degree equation has the following form:

ax^2 + bx + c

so a = 1, b = -8 and c = 7. Now you have to substitute in the previous equation

x = - (-8) / 2(1)

x = 8 / 2

x = 4

This means that the two functions have the same x-value.

The y value of f(x) would be

f(4) = (4)^2 - 8(4) + 7

f(4) = 16 - 32 + 7

f(4) = -9

So the vertex, or minimun value of f(x) would be at the point (4, -9).

The vertex, or minimun value of g(x) is at the point (4, -4).

So f(x) has a minimum value of -9 and g(x) a minimum value of -4.

has the greater minimum at

Step-by-step explanation:

The given function is

Additionally, the graph attached shows the function which as a minimum at (4,-4).

So, let's find the minimum of , which has coordinates where is defined as

Where and , replacing these values, we have

So, the other coordinate is defined as , so replacing the value in the function, we have

So, the minimum of is at .

Therefore, has the greater minimum at

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step-by-step explanation: vsfdvsfvd