Create the equation of a cubic in standard form that has a double zero at -2, another zero at 4, and a y-intercept of 16,

f(x) = x³ - 3x - 4

Step-by-step explanation:

Given that x = - 2 has multiplicity 2 and x = 4 are zeros then

(x + 2)² and (x - 4) are the factors of the polynomial and the polynomial is the product of the factors, thus

f(x) = a(x + 2)²(x - 4) ← a is a multiplier

To find a substitute (0, 16) into the equation

16 = a(4)(16), thus

64a = 16

a = =

f(x) = (x + 2)²(x - 4) ← expand factors

    = (x² + 4x + 4)(x - 4)

    = (x³ + 4x² + 4x - 4x² - 16x - 16)

    = (x³- 12x - 16)

   = x³ - 3x - 4

step-by-step explanation:

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)