Quick.
what is the equation of the quadratic graph with a focus of (5, −1) and a directrix of y = 1?

f(x) = − one fourth (x − 5)2 + 1

f(x) = one fourth (x − 5)2 + 1

f(x) = − one fourth (x − 5)2

f(x) = one fourth (x − 5)2

The answer to your question is: third option is correct

Step-by-step explanation:

Data

F (5, -1)

directrix   y = 1

Then, after getting the graph, the vertix = (5, 0)

                                                        and p = 1

                 Formula

                              (x - h) ² = -4p(y - k)

                              (x - 5)² = -4(1)(y - 0)

                              (x - 5)² = -4y

                              y = (x - 5)² / -4

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

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step-by-step explanation:

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