Start with the logistic equation dx dt = kx(m x). suppose we modify our harvesting. that is we will only harvest an amount proportional to current population. in other words, we harvest hx per unit of time for some h > 0 (similar to earlier example with h replaced with hx). a) construct the di erential equation. b) show that if km > h, then the equation is still logistic. c) what happens when km < h?

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

idk

step-by-step explanation:

they disappear if your absent from to long. i found out that the hard way.

step-by-step explanation:

brainliest lol i just need one more brainliest.