6(2r-2)=-8r+40 what does r
equal

r = -7

Step-by-step explanation:

Solve for r:

-6 (2 r - 2) = 40 - 8 r

Expand out terms of the left hand side:

12 - 12 r = 40 - 8 r

Add 8 r to both sides:

8 r - 12 r + 12 = (8 r - 8 r) + 40

8 r - 8 r = 0:

8 r - 12 r + 12 = 40

8 r - 12 r = -4 r:

-4 r + 12 = 40

Subtract 12 from both sides:

(12 - 12) - 4 r = 40 - 12

12 - 12 = 0:

-4 r = 40 - 12

40 - 12 = 28:

-4 r = 28

Divide both sides of -4 r = 28 by -4:

(-4 r)/(-4) = 28/(-4)

(-4)/(-4) = 1:

r = 28/(-4)

The gcd of 28 and -4 is 4, so 28/(-4) = (4×7)/(4 (-1)) = 4/4×7/(-1) = 7/(-1):

r = 7/(-1)

Multiply numerator and denominator of 7/(-1) by -1:

 r = -7

i hope this is what you were looking for.

see attached graph

95.03 is the answer. hope this !