If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at random (assume the child may write the same letter twice), what is the probability that one is a vowel and the other is a consonant?

Step-by-step explanation:

In probability

Here, we want P(vowel) "AND" P(consonant). So we find individual probabilities and "MULTIPLY" them.

Firstly, P(vowel):

From the letters  a,b,c,i,e ------  we know 2 are vowel and 3 are consonants (total 5)

Hence, P(vowel) = 2/5

Second, P(consonant):

There are 3 consonants, hence

P(consonant) = 3/5

Now, we multiply:

P(vowel and consonant) = P(vowel) * P(consonant) = 2/5 * 3/5 = 6/25

The probability that one is vowel and the other is a consonant =

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

cheater

step-by-step explanation: