Tyler has some pennies and some nickels. he has no less than 15 coins worth at most
$0.55 combined. if tyler has 7 pennies, determine the maximum number of nickels
that he could have. if there are no possible solutions, submit an empty answer.

He only can have 9 nickels.

Step-by-step explanation:

Let's define P as the number of pennies and N as the number of nickels.

P + N > 15

because he has no less than 15 coins in total.

and:

P*$0.01 + N*$0.05 ≥ $0.55

Because he has at most, $0.55

Now, if  P = 7

Now we need to solve:

7*$0.01 + N*$0.05 ≥ $0.55

N*$0.05 ≥ $0.55 - $0.07 = $0.48

Now, with the equality of this relation, we can find the maximal value of N.

N*$0.05 = $0.48

N = 0.48/0.05 = 9.6

So the maximum number of nickels he can have is 9.6, but he can not have a 0.6 of a nickel, so we need to round down to 9.

Now, we also know that he no less than 15 coins in total, with that equation we can find the minimal value of N.

7 +  N  > 15.

N > 15 - 7 = 8

So we have the range:

8 < N ≤ 9

This means that the only possible value of N is 9

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.