Triangle e d f has sides that are of varying lengths. side e d has a length of 4 and side e f has a length of 9.
which statements about the diagram are true? select three options.

d e + e f greater-than d f
triangle d e f is an isosceles triangle.
5 less-than d f less-than 13
d e + d f less-than e f
triangle d e f is a scalene triangle.

D E + E F greater-than D F

5 less-than D F less-than 13

Triangle D E F is a scalene triangle

Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

we have the triangle EDF

where

Applying the triangle inequality theorem

1)

2)

so

The length of DF is the interval -----> (5,13)

The triangle DEF is a scalene triangle (the three length sides are different)

therefore

The statements that are true are

D E + E F greater-than D F

5 less-than D F less-than 13

Triangle D E F is a scalene triangle

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source