Two rectangles or similar one is 5 cm x 12 cm the long side of the second rectangle is 8 cm greater than twice is short side find its length and width

The length is 48

The width is 20

Step-by-step explanation:

When 2 rectangles (figures) are similar, the ratio of corresponding sides are equal.

This rectangle is 5 by 12, so the shorter side (corresponding to 5) to the longer side (corresponding to 12) would be the same ratio, 5:12.

Let shorter side be s, and

longer side be l

It says, long side is 8 greater than twice short, we can write this as:

In similar rectangles, we have said the corresponding sides' ratio are equal, so we could write:

Now, we replace the new found expression for "l" onto this and cross multiply and solve for s first:

So the shorter side is 20. and hence the longer side would be:

l = 2s + 8

l = 2(20) + 8

l = 40 + 8

l = 48

The longer side is 48.

The length is 48

The width is 20

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it