There are 4 different math courses, 5 different science courses, and 2 different history courses. if a student must take one of each, how many different ways can this be done?

A student can take three subjects in 40 ways.

SOLUTION:

Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.

A student must take one of each, how many different ways can this be done?

Now, number ways to take math course = 4

Number of ways to take science course = 5  

Number of ways to take history course = 2

So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.

Hence, a student can take three subjects in 40 ways.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

1. supplementary angles

2. acd and bcd

step-by-step explanation: