A95% confidence interval for a population mean, μ, is given as (18.985, 21.015). this confidence interval is based on a simple random sample of 36 observations. calculate the sample mean and standard deviation. assume that all conditions necessary for inference are satisfied. use the t-distribution in any calculations.

standard deviation of the sample =  s = 3.04

Step-by-step explanation:

given,

μ, is given as (18.985, 21.015)

sample mean =

                      =19.9865

margin of error = 19.9865 - 18.958 =1.0285

The degree of freedom = n -1 = 36 - 1 = 35

a = 0.05,  t(0.025, df = 35) = 2.03 (from student t table)

margin error =

      =

      =

      =

      = s = 3.04

standard deviation of the sample =  s = 3.04

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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