Each of the following integrals represents the area of either a triangle or part of a circle, and the variable of integration measures a distance. in each case, say which shape is represented, and give the radius of the circle or base and height of the triangle. you will find it useful to make a sketch of the region, showing the slice used to find the integral, labeling the variable and differential on your sketch. then evaluate the integral to find the area.

a. \int_0^{3} 3 x\,dx
which is the shape of the region being integrated?
a. triangle
b. part of a circle

radius, or base and height =
(if you are entering a base and height, enter them separated by a comma, e. g., 4, 3)

area =

b. \int_0^{\sqrt{5}} \sqrt{5 - h^2}\,dh
which is the shape of the region being integrated?
a. triangle
b. part of a circle

radius, or base and height =
(if you are entering a base and height, enter them separated by a comma, e. g., 4, 3)

area =

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

50x5=$250

step-by-step explanation:

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)