What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)? !

(y-5) = (6/7)(x-4) or  (y+1) = (6/7)(x+3)

Step-by-step explanation:

point-slope form is

(y-y1) = m(x-x1), where m is a slope , and x1 and x1 are coordinate of the point.

m=(y2-y1)/(x2-x1) = (5-(-1))/(4-(-3))=6/7, slope m=6/7

We can use any point to write a point-slope form of an equation

1) (y-5) = (6/7)(x-4)

or

2) (y+1) = (6/7)(x+3)

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363