Aphysician orders aminophylline 7.5 mg per kg of body weight. the patient weighs 110 lb. if aminophylline is available in 0.125-g tablets, how many tablets should patient receive?

The patient will receive 2 whole tablets.

Step-by-step explanation:

The total weight of the drug to be administered can be expressed as;

Total dose of aminophylline to be administered=Dose per weight of patient×weight of patient

where;

Dose per weight of patient=7.5 mg per kg

weight of patient=110 lb

1 kilogram=2.205 lb

weight of patient in kilograms=110/2.205=49.89 kilograms

replacing;

Total dose of aminophylline to be administered=Dose per weight of patient×weight of patient

Total dose of aminophylline to be administered=(7.5×49.89)=374.175 mg

Total weight of tablets=374.175 mg

Total weight of tablets=weight per tablet×number of tablets

where;

Total weight of tablets=374.175 mg

Weight per tablet=0.125 g

1 gram=1000 mg

Weight per tablet in mg=(1,000×0.125)=125 mg

Number of tablets=n

replacing;

Total weight of tablets=weight per tablet×number of tablets

374.175=125×n

n=374.175/125

n=2.9934

The patient will receive 2 whole tablets.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;