2problems show work
1. use synthetic division to find the zeroes of the function f( x )=x^3+x^2+4x+4
2. find the sum. write your answer in simplest form. (x − 4)/ (x^2 − 2x) + (4)/ (x^2 − 4)

1st problem:

-1, 2i, -2i

Set the function equal to 0 and divide for x

0=x^3+x^2+4x+4

Subtract 4 from both sides leaving you with

-4=x^3+x^2+4x

divide both sides by four

-4÷4= -1

That is how you get -1

you now have -1=x^2+x^3+x

Solve for x buy finding the square roots of x^2, x^3 and subtracting x from both sides and you get 2i, -2i

Your answer to number one is -1, 2i, -2i

Second problem:

Find the LCD to be able to add these first

The LCD of (x-4)/x^2-2x is

x(x-2)

That is the first side done

The second side's LCD is (x+2)(x-2)

Now you can add the two together

x(x-2)+(x+2)(x-2)=

Your answer in fraction form is

(x+4)/x(x+2)

the solution is h=10 because you add 9 to each side of the equation.

step-by-step explanation: