Agroup of 20 students are being asked to report the number of pets they keep in their house the results are 0,0,0,0,0,1,1,1,1,1,1,1,1,2,2,3,4,4 ,4,21

mean is 2.4
standard deviation is 4.47
quartile 1 is 0.5
median is 1
quartile 3 is 2.5

after being told that they should not count any fish in the report, the value of 3 becomes a 2 and the value of 21 becomes 1. would these changes affect the median, mean, standard deviation or inter quartile range ? if so would each measure decrease or increase from their original values?

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer is c

hope this !

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

table 3 represents a direct variation function. : )