Determine dois números ímpares consecutivo cujo produto seja 195

Let 1st integer  = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0

We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78 
We determine which value of x when substituted gives us a product of 195. 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 The solution is 2 sets of two consecutive number Set 1 The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48 
Set 2 The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)