There are two values of a for which the equation 5x2+ax+7x+5=0 has only one solution for x. what is the sum of those values of a?

-14

Step-by-step explanation:

First of all, we know that 5x^2+ ax+7x +5=0 only has one root. That means that b^2 - 4ac=0, and we can use this to find the discriminant, ax + 7x.

Now, if we simplified 5x^2+ ax+7x +5=0, by dividing it all by 5, it would be x^2+(a+7)/5x + 1 = 0.

After, we can plug what we know into the formula, b^2 - 4ac=0. It would be:

(a+7)^2 / 25 - 4 = 0

(a+7)^2 / 25 = 4

(a+7)^2 = 100

Since this is a square root, a+7 can be both negative or positive.

a+7= 10, or a+7 = -10

a=3, or a=-17

The question asks for the sum of a, which is 3 + (-17) = -14

Therefore, the answer is -14.

:) have fun with your rsm problems, assuming you got this from the portal.

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: