What is the value of the slope of the tangent line to a relative maximum of a function?

Slope is zero at relative maximum.

Step-by-step explanation:

If a function has a relative maximum at x =a, then the tangent line to the function at that point is parallel to the x axis.

We know that, a line parallel to x axis is of the form , where, is the y intercept of the line.

Also, can be rewritten in slope-intercept form as:

On comparing the above equation with the standard form , we conclude that, for the line . Therefore, the slope of the line of the form  is 0. Hence, the slope of the tangent line to the relative maximum is zero.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1