Atrebuchet launches a projectile from ground level on a parabolic arc at a velocity of 40 feet per second. the equation h = -16t^2+40t models the projectiles height at t seconds. how long will it take for the projectile go hit it’s target on the ground?

The projectile hits the target after 2.5 seconds.

Solution:

Given, A trebuchet launches a projectile from ground level on a parabolic arc at a velocity of 40 feet per second.  

The equation h = -16t^2+40t models the projectiles height at t seconds.  

We have to find how long will it take for the projectile go hit it’s target on the ground?

Now, when the projectile hits its target on ground, its height becomes 0

neglect t = 0 as it represents initial phase of projectile.

16t = 40  

t = 2.5

Hence, the projectile hits the target after 2.5 seconds

it’s supposed to be -4+45=41

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb