what is the area of a triangle with vertices at
(0, −2) ,(8, −2) , and (9, 1) ?
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The area of a triangle with vertices at  (0, −2) ,(8, −2) and (9, 1) is 12 square units

Solution:

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

The area of triangle when vertices are given is:

Here in our problem,

Now, substitute the above values in the formula:

Hence, the area of the triangle is 12 square units.

21

step-by-step explanation:

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: