In parallelogram abcd , m∠a=(2x)° and m∠b=(5x+5)° . the figure shows parallelogram a b c d with vertices named clockwise from bottom left. what are the measures of the angles of the parallelogram? enter your answers in the boxes. m∠a= ° m∠b= ° m∠c= ° m∠d= °

The measure of angles of parallelogram are

∠A = 50° ,

∠B = 130° ,

∠C = 50° ,

∠D = 130°

Step-by-step explanation:

Given as for a parallelogram :

The vertices of parallelogram is A B C D in clockwise

The measure of angle A = ∠A =  ( 2 x )°

The measure of angle B =  ∠B =  ( 5 x + 5 )°

Now, for a parallelogram , the sum of measure of all four angles = 360°

From The property of Parallelogram

A ) The adjacent angles are supplementary

So, ∠A + ∠B =  180°

Or, ( 2 x )° + ( 5 x + 5 )° = 180°

Or, ( 7 x + 5 )° = 180°

Or , ( 7 x )° = 180° - 5°

Or , ( 7 x )° = 175°

∴   x =

I.e x = 25°

So,  ∠A =  ( 2 x )° =  ( 2 ×25° )

I.e , ∠A = 50°

 ∠B =  ( 5 x + 5 )°

Or, ∠B =  ( 5 ×25° + 5 )°

I.e ,  ∠B = 130°

B ) The opposite angles of parallelogram is equal

   So,  ∠C =  ∠A = 50°

I,e   ∠C = 50°

And ∠D = ∠B = 130°

I.e  ∠D = 130°

Hence The measure of angles of parallelogram are ∠A = 50° , ∠B = 130° , ∠C = 50° , ∠D = 130°  Answer

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.