Given the relations a: (3,2), (5,3), (6,2), (7,4) which statement is true?

both a and a^-1 are functions

neither a nor a^-1 is a function

only a is a function

only a^-1 is a function

Option 3.

Step-by-step explanation:

The given relation is

A= {(3,2), (5,3), (6,2), (7,4)}

A relation is called a function, if there exist a unique value of y for each value of x.

In relation A, there exist unique output for each input. So, A is a function.

If a relation is defined as R = {(a,b), a∈R,b∈R}, then inverse of R is

R⁻¹ = {(b,a), a∈R,b∈R}

So, inverse of A is defined as

A⁻¹= {(2,3), (3,5), (2,6), (4,7)}

Here, the value of y are 3 and 6 at x=2.

For x=2, there exist more than one output. So, A⁻¹ is not a function.

Therefore, the correct option is 3.

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!

answer: f = 32.2m

step-by-step explanation: that is the answer