G(x) = (x-5)^2 + 4 what is quadratic equation in standard form

a. g(x)=x^2 +10x+21
b. g(x)=x^2 +10x+29
c. g(x)=x^2 -10x+29
d. g(x)=x^2 -10x+21

C is the answer

g(x)  = x² - 10 x + 29

Step-by-step explanation:

g(x) = (x -5)² + 4

       = x² - 10 x +25 +4

        = x² - 10 x + 29

∴ g(x)  = x² - 10 x + 29

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

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