Whats the algebraic equation for: jorge has some dimes and quarters. he has 10 more dimes than quarters and the collection of coins is worth $2.40. how many dime and quarters does jorge have?

4 quarters and 14 dimes

Step-by-step explanation:

Let x be quarters and since Jorge has 10 more dimes than quarters you can say x + 10. 25 is the quarters and the 10 is the dimes.  

25x + 10(x+10) = 240

25x + 10x + 100 = 240

35x = 140

x = 4

Multiply 4 and 0.25 and you get 1.00. Subtract 1.00 from 2.40 to get 1.40. Divide that by 10 (amount of dime) to get 14.

1,150 give brainliest

step-by-step explanation

2r= 2300

r =1150

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64