The daredevil cliffs rise vertically from the beach. the beach slopes gently at an angle of 3 feet from the horizontal. laying at the water's edge, 50 feet from the base of the cliff, you determine your position, and a straight line to the top of the cliff creates an angle of 70 degrees with the line to the base of the cliff. how high is the daredevil cliff?

160.70 ft. ( approx )

Step-by-step explanation:

Let AB represents the cliff, C represents Scott's position,

Then according to the question,

m∠ABC = 93°, ( because beach slopes gently at an angle of 3 feet from the horizontal )

m∠ACB = 70°,

BC = 50 ft,

∵ The sum of all interior angles of a triangle is 180°,

i.e. m∠ABC + m∠ACB + m∠BAC = 180°,

⇒ 93° + 70° + m∠BAC = 180°,

⇒ m∠BAC = 180° - 163° = 17°,

By the law of sine,

Hence, daredevil cliff is approximately 160.70 ft.

1 and 2

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: