Sales personnel for skillings distributors submit weekly reports listing the customer contacts made during the week. a sample of 65 weekly reports showed a sample mean of 19.5 customer contacts per week. the sample standard deviation was 5.2. provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel.

As per given , we have

sample size : n= 65

degree of freedom : df=n-1=64

sample mean :

sample standard deviation : s= 5.2

Since , the population standard deviation is not given  , so we apply t-test.

Significance level  for 90% confidence :

t-critical value for significance level 0.10 and df = 64 would be :

Formula for Confidence interval :

Then , 90%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

∴ 90% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.424, 20.576)

Significance level  for 95% confidence :

t-critical value for significance level 0.05 and df = 64 would be :

Then , 95%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

∴ 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.212, 20.788)

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

answer:

a=9

step-by-step explanation: lmk if you need a explanation