Answer the following questions about the standard normal random variable z. (use 4 decimal places in your answers to parts a. through f.) a. what is p(-1.46 < z < 0. response) b. what is p(0 < z < 1. response) c. what is p(z > -1. response) d. what is p(z < -2. response) e. what is p(z < 2. response) f. what is p(-2.58 < z < -1.1)?

a) 0.6636

b) 0.0951

c) 0,9474    

d)  0.0047

e) 0.9957  

f)   0.1308  

Step-by-step explanation:

We look in tables z values and then we see carefully aereas inside normal curve

a) P[- 1.46 < z < 0.63 ]     point 1.46 from table 0.0721  this s th area from value -1.46 to the left . And the value  z = 0.63  corresond to the area 0.7357 which includes the area between 1.46 to the left tail, then we have to subtarct and get 0.6636 .

P[- 1.46 < z < 0.63 ] = 0.6636             66.36 %

b) P [ 0 < z < 1.31 ] we just need the area for point 1.31   that is 0.0951

P [ 0 < z < 1.31 ] = 0.0951                   9.51 %

c)  P [z > - 1.62  ] = 1 - 0.0526

P [z > - 1.62  ] = 0,9474                       94.74 %

d) P[z < - 2.6 ] =   0.0047                       0.47 %

e) P [ z < 2.63 ] = 1 - 0.0043

P [ z < 2.63 ] = 0.9957                         99.57 %

f) P [ -2.58 < z < -1.1 ]  =  0.1357 - 0.0049 =  

P [ -2.58 < z < -1.1 ]  =  0.1308              13.08 %

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi