Atextile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. the company wishes to test the hypothesis against using a random sample of specimens. calculate the p-value if the observed statistic

P-value= 0.028834

Step-by-step explanation:

The test statistic value is: 11.25 12 -3 0.5

Since this is a left tailed test, so the p-value is given by:

P(t-1 3 P(t3<-3)=P(t3 > 3) = 0.028834

Please see the see attachment .

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

0/5 is 0, 2/0 is undefined, and 0/0 is indeterminate.

step-by-step explanation:

hope my answer has you!