Calculus
the following curve passes through (3,1)
using linear lineralization

Option 1.1

Step-by-step explanation:

The linearization of a curve implies the use of calculus to find the local value for the derivative and approximating the function by the use of the formula

The function is given in such way that it's much easier to find the derivative by implicit differentiation than isolating any of the variables

Differentiating with respect to x, we have

Computing y' in the given point (3,1) we have

4(3)(1)+2(9)y'+y'=2

The function will be approximated with the expression

To find the approximate value for x=2.8

The correct value is the option 1.1

w'x is 0.

hope it