The measure of one of the angles formed by two parallel lines and a transversal is 5°. is it possible for the measure of any of the other seven angles to be equal to 85°? explain.

Step-by-step explanation:

It is given that there are 2 parallel lines 'l','m' and let 'n' be the traversal line.

One of the 8 angles formed is 5°.

Therefore the angle beside to this angle should obviously be an obtuse angle which is 175°, since it lies on a straight line.

It is clear that all the 4 angles at this intersection point are 5°,5°,175°,175° and they add up to 360° since they are angles around a point.

Now for the other intersection point, opposite angles are supplementary

therefore even here the same story repeats.

All the 4 angles at this intersection point also are 5°,5°,175°,175° and they add up to 360° since they are angles around a point.

Therefore there is no possibility for an angle 85° to exist.

Please check out this website if you are interested :

https://www.mathwarehouse.com/geometry/angle/parallel-lines-cut-transversal.php

2nd one in the first row is correct

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~