The lifetime of a lightbulb can be modeled with an exponential random variable with an expected lifetime of 1000 days. (a) find the probability that the lightbulb will function for more than 2000 days. (b) find the probability that the lightbulb will function for more than 2000 days, given that it is still functional after 500 days

a) 0.13533

b) 0.36788

Step-by-step explanation:

Let X be the random variable that measures the lifetime of a bulb.

If the random variable X is exponentially distributed and X has an average value of 1000 days, then its probability density function is

and its cumulative distribution function (CDF) is

(a) Find the probability that the light bulb will function for more than 2000 days

(b) Find the probability that the light bulb will function for more than 2000 days, given that it is still functional after 500 days

Let A and B be the events,

A = “The bulb will last at least 2000 days”

B = “The bulb will last at least 500 days”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

We have  

hence,

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

lol

step-by-step explanation: