According to data from the 2010 united states census, 43.1% of americans over the age of 65 were male.
suppose maria, a researcher, takes a random sample of 60 americans over the age of 65 and finds that 18 are male.
let p represent the sample proportion of americans over the age of 65 that were male.

what are the mean and standard deviation of the sampling distribution of p?

Step-by-step explanation:

The mean and standard deviation of the sampling distribution of p is given by :-

, where p= population proportion.

n= sample size.

Let p represent the sample proportion of Americans over the age of 65 that were male.

Given : The proportion of Americans over the age of 65 were male.

p= 43.1%=0.431

sample size : n= 60

Then, the mean and standard deviation of the sampling distribution of p will be :-

Hence, the mean and standard deviation of the sampling distribution of p :

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3