As part of a quality-control program, the chess sets manufactured by jones brothers are subjected to a final inspection before packing. the rate of increase in the number of sets checked per hour by an inspector t hr into the 8 a. m. to 12 noon shift is approximately:
n'(t) = −3t^2 + 12t + 45 (0 < _ t < _4).
(a) find an expression n(t) that approximates the number of sets inspected at the end of t hours.

Step-by-step explanation:

Since we have given that

in between (0≤t≤4).

We need to find N(t) that approximates the number of sets inspected at the end of t hours.

So, it becomes,

Hence,

4

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2