Look at the picture. i need to find svt. the answer is 17 degrees but i don't know how to get that answer working it out.

∠ SVT = 18.5 degrees

Step-by-step explanation:

See the given figure.

This is a diagram of a rhombus and the opposite angles of a rhombus are the same.

Now, ∠ VST = 5x + 23 and ∠ VUT = 8x - 49

And we have ∠ VST = ∠ VUT {Opposite angles}

So, 5x + 23 = 8x - 49

⇒ 3x = 23 + 49 = 72

⇒ x = 24

So, ∠ VST = 5x + 23 = 5 × 24 + 23 = 143

Hence, the other two opposite angles of the rhombus are degrees each.

So, 2 × ∠ SVT = ∠ SVU = 37

⇒ ∠ SVT = 18.5 degrees (Answer)

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.