Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3) represents linear function. is she correct. explain your reasoning

The graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function

Step-by-step explanation:

Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3)

Now, the line joining (-3,-3) and (-3,0) has slope = = ∞

Again, the line joining (-3, 0) and (-3,3) has slope = = ∞

Therefore, both the lines are parallel to y-axis and has a common point (-3,0). {Since, tan Ф = ∞, ⇒ Ф = 90°}

So, the graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function as the graph represents a vertical line parallel to y-axis. (Answer)

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: