You are a construction worker who is laying down concrete drainage pipes. each pipe is 5 feet long and 3 inches thick, and has an outside diameter of 6.5 feet. you lay down 4 drainage pipes end to end. at any given time, what is the volume of water that passes through the 4 drainage pipes at half capacity? round the answer to the nearest tenth of a cubic foot.

the volume of water is approximately 940 cubic foot

Step-by-step explanation:

1.we know the volume of given one single pipe

2.they given total 4 pipes with half capacity and asked the volume of water at any given time

3.VOLUME OF SINGLE PIPE =π×R1²×H-π×R2²×H

4.where R1 IS radius of outer edge and R2 is radius of inner edge and H is height of given pipe

5.GIVEN R1 is 6.5 feet and R2 is [6.5-3] feet because given thikness of pipe is 3 feet so we have to subtract this from 6.5 that is 3.5 feet

6.total volume= 4×volume of one single pipe.

7.volume of water is half of of total volume because given of half capacity.

8.volume of single pipe is=π×5×10×3=150π

9.total volume =600π

10.volume of water is 300π≈940 cubic foot

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

step-by-step explanation: