Apulley of radius 10 cm turns at 6 revolutions per second. what is the linear velocity of the belt driving the pulley in meters per second?
possible answers:
a. 376.99 m/s
b. 1.67 m/s
c. 166.67 m/s
d. 3.77 m/s

This problem is on the circular motion.

Assuming a basis of 1 sec, there would be 6 revolutions, which is equivalent to 6 circumference of the pulley. One revolution means one circumference, which is 2(pi)(10cm) or 20(pi) cm.

Therefore, linear speed is 6(20)(pi) cm/s or 376.99 cm/s or 3.77 m/s

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: