Dr. christina cuttleman, a nutritionist, claims that the average number of calories in a serving of popcorn is 75 with a standard deviation of 7. a sample of 50 servings of popcorn yields an average of 78 calories.
a. should z test or t test be used?
b. check dr. cuttleman's claim at a = 0.05.

a) T test

b) Claim

because critical value is not equal to test statistic then reject null hypothesis

Step-by-step explanation:

Construction of hypothesis

H₀  : p = 75

H₁  : p  ≠ 75

Here Standard deviation = 7

sample = n = 50

Average = x-bar = 78

Level of significance:

∝ = 5% = 0.05

Degree of freedom:

df = n-1

  = 50 -1 = 49

Critical value :

± 1.96

a) T test

test t is  used as average X mean is used

Test Statistic:

t = X₂ - X₁ / Sd /√n

= 78 - 75 / 7/√50

=3.0304

Critical region :

We take two tail T test

test statistic is in reject interval. Reject H₀

b) Claim

because critical value is not equal to test statistic then reject null hypothesis

step-by-step explanation:

my butt

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5