Tickets were sold to the public for 8.00$ each and sold to students for 3.00$ a piece. there were a total of 400 tickets sold. making a total revenue of 1900.00$. how many tickets were sold to the public and how many tickets were sold to students

140 tickets were sold to public and 260 tickets were sold to students

Let "p" be the number of tickets sold to public

Let "s" be the number of tickets sold to students

Cost of one ticket sold to public = $ 8.00

Cost of one ticket sold to student = $ 3.00

There were a total of 400 tickets sold

number of tickets sold to public + number of tickets sold to students = 400

p + s = 400 -------- eqn 1

Making a total revenue of 1900.00$

number of tickets sold to public x Cost of one ticket sold to public + number of tickets sold to students x Cost of one ticket sold to student = 1900.00

8p + 3s = 1900 ------ eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "s"

Multiply eqn 1 by 3

3p + 3s = 1200 ---- eqn 3

Subtract eqn 3 from eqn 2

8p + 3s = 1900

3p + 3s = 1200

(-) ------------------

5p = 700

Substitute p = 140 in eqn 1

p + s = 400

140 + s = 400

Thus 140 tickets were sold to public and 260 tickets were sold to students

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1