Ineed

find the midpoint for cd whose endpoints have coordinates (6,6) and (-2,2)

(2,4)

Step-by-step explanation:

Add the X-coordinates  for both points and divide by 2

which now becomes 6+(-2)=4

Now divide 4 by 2 : 4/2 = 2

Add the Y-coordinates  for both points and divide by 2

which now becomes 6+2=8

Divide 8 by 2 : 8/2 = 4

Bring the X and the Y together which becomes (2,4)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: