An online furniture store sells chairs for $150 each and tables for $550 each. the store must sell at least $8500 worth of chairs and tables each day. write an inequality that could represent the possible values for the number of tables sold, tt, and the number of chairs sold, cc, that would satisfy the constraint.

The solution is not possible for the number of chair to be sold 18 , It is only possible if the number of chair to be sold is 11 and the number of tables to be sold is 9  .

Step-by-step explanation:

Given as :

The cost of each chairs = $ 150

The cost of each tables = $ 350

The maximum number of chair and table can ship = 20

The minimum selling amount of chairs and tables = $ 4800

Let The number of chair to be ship = C

And The number of table to be ship = T

So , According to question

C + T = 20         1

And $ 150 × C + $ 350 × T = $ 4800         2

So, From first eq

$ 150 × ( C + T ) = $ 150 × 20

Or, $ 150 C + $ 150 T = $ 3000

So, Solving eq

( $ 150 × C + $ 350 × T ) - ( $ 150 C + $ 150 T ) = $ 4800 - $ 3000

Or, ( $ 150 C - $ 150 C ) ( $ 350 T - $ 150 T ) = $ 1800

Or, 0 + $ 200 T = $ 1800

Or,  T =

∴  Number of Tables T = 9

So, Number of chairs C = 20 - T = 20 - 9 = 11

Thus to meet the requirement The number of Tables to be sold = 9 and the number of chairs to be sold = 11

But , If the number of chair to be sold = 18

And Since The maximum of pieces of furniture to be sell = 20

So, The number of tables to be sold = T = 20 - 18 = 2

∴ For table T = 2 And chair C = 18

Let check the net worth

I.e ( $ 150 × C + $ 350 × T )

Or, ( $ 150 × 18 + $ 350 × 2 )

Or, $ 2700 + $ 700 = $ 3400

But The company must sell the furniture of net worth at least $ 4800 ,  So this is not possible to sell 18 chair .

Hence The solution is not possible for the number of chair to be sold 18 , It is only possible if the number of chair to be sold is 11 and the number of tables to be sold is 9  . Answer

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!