The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 3 to t = 6 represent?

Average Rate of change of d(t) is 11.43

Step-by-step explanation:

Given:

d(t) = 4.9 t²

where d(t) gives distance covered by coin in time t.

To find: The Average Rate of change of d(t) from t = 3 to t = 6.

We know that Average rate of change, A of f(x) =

here, a= 6 and b = 3

So, Average rate of change =

                                               =

                                               =

                                               =

                                               =

                                               =

Therefore, Average Rate of change of d(t) is 11.43

answer: y=4000x+14000

step-by-step explanation:

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step-by-step explanation: