A32 year old mother realized that her age is twice the sum of her two children's ages. her son, jose is two years older than her daughter, sophia. how old are sophia (x) amd jose (y)?

1,15 2,14 3,13 4,12 5,11 6,10 7,9 8,8 {x,y}

Step-by-step explanation:

There would be multiple answers for this question so what you have to do is find what doubles to 32 which would be 16 so you just have to find two numbers that add to 16 so the answers could be; 1,15 2,14 3,13 4,12 5,11 6,10 7,9 8,8

14,2 (x,y)

Step-by-step explanation:

The mother is 32 with 2 children, so we divide by 2 to get 16. Jose (y) is 2 years older than Sophia (x) so you should subtract 2 from 16 and get 14 meaning that is how old Sophia is.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

step-by-step explanation:

milk=16 large

soda=280 kids

juice box=82 regular

63 soda +63 regular

124 large total