g(x)
ху
-2 10
f(x) = 2 sin(2x - 1) +2
Mathematics, 17.12.2019 22:31 shadow6728g
Compare the following functions:
g(x)
ху
-2 10
f(x) = 2 sin(2x - 1) +2
17
o
onov
4
5
6
which function has the smallest minimum?
all three functions have the same minimum
g(x)
h(x)
Answers: 1
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You know the right answer?
Compare the following functions:
g(x)
ху
-2 10
f(x) = 2 sin(2x - 1) +2
g(x)
ху
-2 10
f(x) = 2 sin(2x - 1) +2
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