The greatest of four consecutive even integers is 14 less than twice the smallest integer. what are the integers

The four consecutive even integers are 20, 22, 24, 26

Solution:

Let the four consecutive even integers are a , a + 2, a + 4, a + 6

Let "a" be the smallest integer and "a + 6" be the largest integer

To find: the four consecutive even integers

Given that the greatest of four consecutive even integers is 14 less than twice the smallest integer

largest integer = twice the smallest integer - 14

a + 6 = 2(a) - 14

a + 6 = 2a - 14

a - 2a = -14 - 6

-a = -20

a = 20

Thus the four consecutive even integers are:

a = 20

a + 2 = 20 + 2 = 22

a + 4 = 20 + 4 = 24

a + 6 = 20 + 6 = 26

Thus the four consecutive even integers are 20, 22, 24, 26

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

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step-by-step explanation: