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mai biked 7 and 1/4 miles today, and noah biked latex: 3\frac{5}{8}3 5 8 miles. how many times the length of noah's bike ride was mai's bike ride
answer choices
2/3
2
1/2
3/2

Option B

2 times the length of Noah's bike ride was Mai's bike ride

Solution:

Given that Mai biked 7 and 1/4 miles today and Noah biked miles

We have to find how many times the length of Noah's bike ride was Mai's bike ride

Let "a" be the number that denotes how many times the length of Noah's bike ride was Mai's bike ride

From given information,

Distance biked by Mai =

Distance biked by Noah =

So to find how many times the length of Noah's bike ride was Mai's bike ride, we can frame a equation as:

"a" times distance biked by noah is equal to distance biked by mai

Substituting the known values we get,

Thus 2 times the length of Noah's bike ride was Mai's bike ride

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12